F(x)=4x^2+3x+10

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Solution for F(x)=4x^2+3x+10 equation:



(F)=4F^2+3F+10
We move all terms to the left:
(F)-(4F^2+3F+10)=0
We get rid of parentheses
-4F^2+F-3F-10=0
We add all the numbers together, and all the variables
-4F^2-2F-10=0
a = -4; b = -2; c = -10;
Δ = b2-4ac
Δ = -22-4·(-4)·(-10)
Δ = -156
Delta is less than zero, so there is no solution for the equation

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